设
k1(a1+2a2)+k2(a2+2a3)+k3(a3+2a1)=0,
å³è¯k1=k2=k3=0
(k1+2k3)a1+(2k1+k2)a2+(2k2+k3)a3=0
å 为åéç»a1,a2,a3线æ§æ å
³ï¼
æ以
k1+2k3=0
2k1+k2=0
2k2+k3=0
解å¾
k1=k2=k3=0
æ以åéç»b=a1+2a2,b2=a2+2a3,b3=a3+2a1线æ§æ å
³
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