f(x)=2x^3-9x^2 +12x-3
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y'=6x^2-18x+12
=6(x^2-3x+2)
=6(x-1)(x-2)
令y'=0,åx=1æè
x=2ã
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y''=12x-18
=6(2x-3)
令y''=0,åx=3/2.
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