问一下大神这个二重积分怎么解,写一下详细过程谢谢啦
如题所述
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/ca1349540923dd543a21b9b5da09b3de9d824898?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
å¦ä¸å¾æ示ã
温馨提示:答案为网友推荐,仅供参考
相似回答
二重积分(求大神解答,并附上详细过程,谢谢。)答:这个要注意积分次序 曲线y=x^3与直线y=x的交点(0,0)(1,1)∫[0,1]e^x^2∫[x^3,x] dxdy =∫[0,1]e^x^2*(x-x^3)dx =1/2e^x^2[0,1]-1/2∫[0,1]e^x^2*x^2dx^2 =1/2e^x^2[0,1]-1/2e^x^2*x^2[0,1]+∫[0,1]e^x^2dx^2 =1/2e^x^2[0,1]-1...
二重积分的问题,请帮忙解一下答:解:∵f''xy(x,y)dy=d[f'x(x,y)],∴I=∫(0,1)xdx∫(0,1)yd[f'x(x,y)]。而,∫(0,1)yd[f'x(x,y)]=yf'x(x,y)丨(y=0,1)-∫(0,1)f'x(x,y)dy=f'x(x,1)-∫(0,1)f'x(x,y)dy。∴I=∫(0,1)xf'x(x,1)dx-∫(0,1)xdx∫(0,1)f'x(x,y)dy...