解ï¼ï¼1ï¼t=0-æ¶ï¼çµè·¯å¤äºç¨³æï¼çµå®¹ç¸å½äºå¼è·¯ï¼ä¸å¾ï¼ã
æ以ï¼ucï¼0-ï¼=5Ã100/ï¼25+100ï¼=4ï¼Vï¼ã
æ¢è·¯å®çï¼t=0+æ¶ï¼ucï¼0+ï¼=ucï¼0-ï¼=4Vï¼
æ¤æ¶ï¼çµå®¹ç¸å½äºä¸ä¸ª4Vççµåæºï¼å æ¤ï¼
iï¼0+ï¼=4/100=0.04ï¼mAï¼ã
ï¼2ï¼t=âæ¶ï¼çµå®¹æ¾çµå®æ¯è¿å ¥ç¨³æï¼çµå®¹å次ç¸å½äºå¼è·¯ã
æ¾ç¶ï¼ucï¼âï¼=0ï¼iï¼âï¼=0ã
ï¼3ï¼çµè·¯çæçµé»ï¼å¨çµåæºç½®é¶åï¼ä»çµå®¹ä¸¤ç«¯çè¿å»ççæçµé»ï¼
R=100â¥100=50ï¼kΩï¼ãçµè·¯æ¶é´å¸¸æ°ï¼Ï=RC=50Ã1000Ã10/1000000=0.5ï¼sï¼ã
æ以ï¼ucï¼tï¼=ucï¼âï¼+[ucï¼0+ï¼-ucï¼âï¼]e^ï¼-t/Ïï¼=0+ï¼4-0ï¼e^ï¼-t/0.5ï¼=4e^ï¼-2tï¼ ï¼Vï¼ã
iï¼tï¼=0.04e^ï¼-2tï¼ ï¼mAï¼ã