第1个回答 2015-04-12
(1)2x/(x^2-9)+1/(3-x)
=2x/(x^2-9)+(3+x)/(9-x^2)
=2x/(x^2-9)-(3+x)/(x^2-9)
=(x-3)/(x^2-9)
=(x-3)/(x-3)(x+3)
=1/(x+3)
(2)(x^2+4x+4)/(x^2-4)-x/(x-2)
=(x^2+4x+4)/(x^2-4)-x(x+2)/(x-2)(x+2)
=(x^2+4x+4)/(x^2-4)-(x^2+2x)/(x^2-4)
=(2x+4)/(x^2-4)
=2(x+2)/(x+2)(x-2)
=2/(x-2)本回答被网友采纳