输出整数1到1000中能被12整除的数，每行显示8个数，用c语言程序编译……

Question

如题所述

Answer 1

int i = 0;
int count = 0; //统计被12整除个数
for ( i = 1， count =0; i <= 1000; i++ )
{
if ( i % 12 == 0 )

{
printf("%d\t", i);

count ++;

}

if ( count % 8 == 0)

{

printf("\n"); // 八个数据后换行

}

}

Answer 2

#include<stdio.h>
int main()
{
    int i=0,n=12;
    while(n<1000)
    {
        printf("%5d",n);
        n+=12;
        if(i<8)
        {
            i++;
        }
        else
        {
            printf("\n");
            i=0;
        }
    }
    return 0;
}