t=(0,8,15,22,41)F=(13.17,28.02,40.05,42.36,46.05) F=A/[1+exp(-r×(t-tm))]A,r和tm为拟合系数
fun=@(a,t)a(1)./(1+exp(-a(2)*(t-a(3))));
a0=[45 0.1 5];
a=lsqcurvefit(fun,a0,t,F)
请问一下决定系数怎么求