第1个回答 2011-10-23
#include<stdio.h>
#define M 4
#define N 4
void main()
{
int a[N][M], min, times=1;
int* p=a;
for(; p!=(a+N*M) ; ++p)
scanf("%d",p);
p=a;
min = *p;
for(; p!=(a+N*M);++p)
{
if(times == M) {printf("\n");times=1}
printf("%d\t", *p);
++times;
if(*p < min)
min=*p;
}
printf("the min integer is %d\n",min);
}