脱式计算:135×12-135÷1123÷37-37÷3920÷[12×(23+45)]

脱式计算:135×12-135÷1123÷37-37÷3920÷[12×(23+45)].

(1)
13
5
×12-
13
5
÷
1
12

=
13
5
×12-
13
5
×12
=(
13
5
-
13
5
)×12
=0×12
=0;

(2)3÷
3
7
-
3
7
÷3
=7-
1
7

=6
6
7


(3)
9
20
÷[
1
2
×(
2
3
+
4
5
)]
=
9
20
÷[
1
2
×
22
15
]
=
9
20
÷
11
15

=
27
44
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