用c语言怎么编写1-3+5-7+9-...+97-99+101

Question

如题所述

Answer 1

呵呵，上面都有问题 用c语言怎么编写1-3+5-7+9-...+97-99+101 回答： #include<stdio.h> main() { int i,sum=0,sum1=0,sum2=0; for(i=1;i=i+4;i<101) { sum1+=i; for(i=3;i=i+4;i<101) { sum2+=i; } sum=sum1-sum2; printf("the result is : %d",sum); }

Answer 2

#include <cstdio>

  int main(){
   int fl=1,ans=0;
   for (int i=1;i<=101;i+=2,fl*=-1)
     ans+=fl*i;
   printf("%d\n",ans);
  }

Answer 3

int total = 101; for( int i = 1, j = -3; i <= 99; i += 4, j -= 4 ) total += i + j;

Answer 4

#include <iostream>
using namespace std;
int main()
{
int sum = 0;
int k = 1;
for (int i = 1; i <= 101; i += 2)
{
sum += k*i;
k *= -1;
}
cout << "1-3+5-7+...-99+101=" << sum << endl;
return 0;
}

Answer 5

#include<stdio.h> 
int main() 
{int i,s=0;
 for(i=1;i<102;i+=2)
   if(i%4==1)s+=i;
     else s-=i;
 printf("%d\n",s);
 return 0;
}

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