初一数学，化成最简二次根式

Question

如题所述

Answer 1

27/5√[(13²-12²)/27]
=27/5√(5²/27)
=√[(27/5)²*5²/27]
=√27
=3√3

-abc/2√[c³/(2a^4b)]
=-abc/2√[(c²/a^4)*c/(2b)]
=-abc/2*c/a²√[c/(2b)]
=-bc²/(2a)*√[2b*c/(2b)²]
=-bc²/(2a)*1/(2b)*√(2bc)
=-c²/(4a)√(2bc)

希望能帮到你，祝学习进步，记得采纳，谢谢

Answer 2

…稍等追答

第二题可能要分类，水平有限，不敢自作主张

Answer 3