3(m + 5) - 2(n + 3) = - 1 (1)
3(m + 5) +2(n + 3) = 7 (2)
(1) + (2)å¾ï¼ 6( m + 5) = 6 解å¾ï¼ m + 5 = 6 m = 1
æ m + 5 = 6代å
¥ï¼1ï¼å¾ï¼ n + 3 = [3(m + 5) + 1]/2
= (3Ã 6 + 1)/2 = 9.5
æ以ï¼n = 6.5
æ以ï¼åæ¹ç¨ç»ç解æ¯ï¼ m = 1 , n = 6.5
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