已知z=1+i,则(1+z)/(1+z^2)=

Question

已知z=1+i,则(1+z)/(1+z^2)=

Answer 1

z²=2i
(1+z)/(1+z^2)
=(2+i)/(1+2i)
=(2+i)(1-2i)/5
=(4-3i)/5

Answer 2

原式=（1+1+i)/(1+z^2)=(2+i)/(1+1+2i-1)=(2+i)/(1+2i)=(2+i)(1-2i)/(1+4)=(4-3i)/5

Answer 3

(4-3i)/5