利用夹逼定理，求数列极限 lim(1+2∧n+3∧n)∧1╱n

Question

如题所述

Answer 1

极限 = 3
－－－－－－－－－－－－－
解析：
A = lim(3^n)^(1/n) = 3
B = lim(1+2^n+3^n)^(1/n)
C = lim(3^n+3^n+3^n)^(1/n) = lim 3^[(n+1)/n] = 3

因为 A ≤ B ≤ C，且 A = C = 3，
所以 B = 3本回答被网友采纳