6/（x+1）=(x+5)/[x(x+1)] (3-x)/(x-4)+1/(4-x)=1 2/(1+x)-3/(1-x)=6/(x*x-1) (2x-3)/(x-1)=(2x-4)/(2x+3)

如题所述

推荐答案 2011-02-05

6/（x+1）=(x+5)/[x(x+1)]
6x=(x+5) (两边同乘x(x+1))
5x=5 (合并同类项)
x=1

(3-x)/(x-4)+1/(4-x)=1
(3-x)-1=(x-4) (两边同乘(x-4))
2x=6 (合并同类项)
x=3

2/(1+x)-3/(1-x)=6/(x²-1)
2/(1+x)-3/(1-x)=6/[(x-1)(1+x)]
2/(1+x)-3/(1-x)=6 (两边同乘(x-1)(1+x))
2(x-1)+3(x+1)=6
2x-2+3x+3=6 (分配律)
5x=5 (合并同类项)
x=1

(2x-3)/(x-1)=(2x-4)/(2x+3)
(2x-3)(2x+3)=(2x-4)(x-1)
(2x)²-9=2x²-6x+4
2x²+6x-13=0
x=(-6±√(36+4×2×13))/4
x=(-3±√(35))/2

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其他回答

第1个回答 2011-02-05

应该是分成4个题吧
[1] 6/（x+1）=(x+5)/[x(x+1)]
[2] (3-x)/(x-4)+1/(4-x)=1
[3] 2/(1+x)-3/(1-x)=6/(x*x-1)
[4] (2x-3)/(x-1)=(2x-4)/(2x+3)
分别解出
[1] 6/（x+1）=(x+5)/[x(x+1)] 简化6x=x+5, x=1
[2] (3-x)/(x-4)+1/(4-x)=1 简化3-x-1=x-4, x=3
[3] 2/(1+x)-3/(1-x)=6/(x*x-1)简化2(x-1)+3(x+1)=6, x=1，依题意x=1分母为零，所以此题无解
[4] (2x-3)/(x-1)=(2x-4)/(2x+3)简化(2x-3)(2x+3)=(2x-4)(x-1), 2x*x+6x-13=0,
x=[-3±(35)^0.5]/2

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