第1个回答 2023-03-08
以下是Java中求两个数组相加并返回结果的示例代码:
```java
public class ArrayAddition {
public static void main(String[] args) {
int[] arr1 = { 1, 2, 3 };
int[] arr2 = { 4, 5, 6 };
int[] result = addArrays(arr1, arr2);
System.out.print("The sum of the arrays is: ");
for (int i = 0; i < result.length; i++) {
System.out.print(result[i] + " ");
}
}
public static int[] addArrays(int[] arr1, int[] arr2) {
if (arr1.length != arr2.length) {
throw new IllegalArgumentException("Arrays must have the same length");
}
int[] result = new int[arr1.length];
for (int i = 0; i < arr1.length; i++) {
result[i] = arr1[i] + arr2[i];
}
return result;
}
}
```
这个程序定义了一个名为 `addArrays` 的静态方法,该方法接受两个整数类型的数组作为参数,并返回一个整数类型的数组,表示两个输入数组对应位置上的元素之和。在主函数中,创建两个数组并调用 `addArrays` 方法进行计算,然后将结果输出到控制台。运行程序后,输出结果将显示为:
```
The sum of the arrays is: 5 7 9
```
这表明程序正确地计算了两个数组的元素之和,并将结果存储在了一个新的数组中。
第2个回答 2017-08-16
参考
public class SumOfTwoArrays{
public static int[] sumOfTwoArrays(int[] arr1, int[] arr2){
int na = arr1.length;
int nb = arr2.length;
int nc;
int min;
if(na > nb){
nc = na + 1;
min = nb;
}else{
nc = nb + 1;
min = na;
}
int[] c = new int[nc];
int sum = 0;
int carry = 0;
int i = na - 1;
int j = nb - 1;
int k = nc - 1;
while(i >= 0 && j>=0){
sum = arr1[i] + arr2[j] + carry;
i--;
j--;
c[k] = sum % 10;
sum = sum / 10;
carry = sum % 10;
k--;
}
while(i >= 0){ //n2
sum = arr1[i] + carry;
c[k] = sum % 10;
sum = sum / 10;
carry = sum % 10;
i--;
k--;
}
while(j >= 0){ //n1 has exhausted
sum = arr2[j] + carry;
c[k] = sum % 10;
sum = sum / 10;
carry = sum % 10;
k--;
j--;
}
c[k] = carry;
return c;
}
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