è¥æ ¹å·ä¸(a-2014)+(b+2015)²=0ï¼è¯æ±ä»£æ°å¼ï¼a+bï¼ç2014次æ¹çå¼
å 为
æ ¹å·ä¸(a-2014)+(b+2015)²=0
å
a-2014=0 b+2015=0
a=2014
b=-2015
æ以
(a+b)ç2014次æ¹
=ï¼2014-2015ï¼ç2014次æ¹
=ï¼-1ï¼ç2014次æ¹
=1
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