输入百分制成绩对应输出优良中及格不及格的成绩等级c语言用swich表达？

Question

如题所述

Answer 1

代码如下：

---

---

#include <stdio.h>

int main()

{

int grade;

printf("请输入成绩: ");

scanf("%d", &grade);

switch (grade / 10)

{

case 10:

case 9:

printf("优.\n");

break;

case 8:

printf("良.\n");

break;

case 7:

printf("中.\n");

break;

case 6:

printf("及格.\n");

break;

default:

printf("不及格.\n");

}

return 0;

}