Shell 按照字符串长度进行排序

Question

一个文本中有若干行，每一行都有且只有一个字符串，要求按照这个字符串的长度对文本中的每一行进行排序，使得长度最长的的行放第一行，第二长次之，以此类推。。。

Answer 1

假设你的文本叫 file.txt
awk '{print $0" "length($0)}' file.txt | sort -nr -k2 | awk '{print $1}' > tmp.txt

排序后的文本为tmp.txt

举例：
$ cat ./file.txt
test
mytestit
hello
girl
boy
let'sdoit&justdoit.

$ awk '{print $0" "length($0)}' file.txt | sort -nr -k2 | awk '{print $1}' > tmp.txt

$ cat tmp.txt
let'sdoit&justdoit.
mytestit
hello
test
girl
boy

Answer 2

#include<string.h>
void convert(char *a,char *b,char *c);
void main()
{
int i,j;
char a[3][10];
for(i=0;i<3;i++)
{
printf("input the %d string:\n",i+1);
scanf("%s",a[i]);//指针的用法注意点
}
convert(a[0],a[1],a[2]);
printf("after change\n");
for(j=0;j<3;j++)
{
printf("%s ",a[j]);//注意i,j啊，这个错误太隐蔽了
}
}

void convert(char *a,char *b,char *c)
{
char temp[10];
if(strcmp(a,b)>0)
{
strcpy(temp,a);
strcpy(a,b);
strcpy(b,temp);
}

if(strcmp(a,c)>0)
{
strcpy(temp,a);
strcpy(a,c);
strcpy(c,temp);
}

if(strcmp(b,c)>0)
{
strcpy(temp,b);
strcpy(b,c);
strcpy(c,temp);
}

}

Answer 3

假设操作文档为d:\1.txt
输出文件为d:\temp.txt

Dim a()
Private Sub Command1_Click()
Open "d:\1.txt" For Input As #1
Do Until EOF(1)
z = z + 1
ReDim Preserve a(z)
Line Input #1, w
a(z) = Len(w) & "*" & w
Loop
Close
For i = 1 To z - 1
For j = i + 1 To z
t = Split(a(i), "*")
q = Split(a(j), "*")
If Val(t(0)) < Val(q(0)) Then
temp = a(i)
a(i) = a(j)
a(j) = temp
End If
Next j
Next i
Open "d:\temp.txt" For Output As #2
For i = 1 To z
y = Split(a(i), "*")
Print #2, y(1)
Next i
Close
End Sub

Answer 4

[root@localhost ~]# awk ' { print length, $0}' a | sort -n | sed 's/.* //'
a
d
ds
ese
sasd
abcds
dfsafdsa
[root@localhost ~]# cat a
abcds
ds
sasd
dfsafdsa
d
a
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