第2个回答 2011-04-03
Y(V>REF(V,1),3);
T2:=EVERY(C>O AND C>REF(C,1),3);
T3:=MA(C,5)>REF(MA(C,5),1) AND MA(C,10)>REF(MA(C,10),1) AND MA(C,5)>MA(C,10);
T1 AND T2 AND T3;
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对不起,这是通达信的,你试一下改为如下公式:
T1:=COUNT(V>REF(V,1),3)=3;
T2:=COUNT(C>O AND C>REF(C,1),3)=3;
T3:=MA(C,5)>REF(MA(C,5),1) AND MA(C,10)>REF(MA(C,10),1) AND MA(C,5)>MA(C,10);
T1 AND T2 AND T3;