第2个回答 2011-07-10
ContourPlot3D[x^2 + y^2 + z^2 - 1, {x, -1, 1}, {y, -1, 1}, {z, -1, 1}]
不能输成x^2 + y^2 + z^2 == 1的形式,那个是Solve的
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/0b55b319ebc4b7458479b444cffc1e178b8215f6?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
本回答被提问者采纳
第3个回答 2011-06-26
ContourPlot3D[
x^2 + y^2 + z^2 == 1, {x, -1, 1}, {y, -1, 1}, {z, -1, 1},
BoundaryStyle -> Directive[Red, Thick], Mesh -> None]
在微积分和作图方面,哪款要更好一些?
都差不多。