vb.net使用打开对话框,打开一个文本文件显示在文本框中,然后对文本框中的信息进行编辑后

Question

如题所述

Answer 1

读文件内容到TextBox :
Try
Using sr As StreamReader = New StreamReader("C:\\TestFile.txt")
textbox1.Text = sr.ReadToEnd()
End Using
Catch E As Exception
Console.WriteLine(E.Message)
End Try

修改完成后,保存到文件:
Using sw As StreamWriter = New StreamWriter("C:\\TestFile.txt")
sw.Write(textbox1.Text)
sw.Close()
End Using

其中,流构造的参数
New StreamReader("C:\\TestFile.txt")
New StreamWriter("C:\\TestFile.txt")
中的"C:\\TestFile.txt"可以用OpenFileDialog和SaveFileDialog的FileName属性替换.
Dim openFileDialog1 As New OpenFileDialog()
openFileDialog1.InitialDirectory = "c:\"
openFileDialog1.Filter = "txt files (*.txt)|*.txt|All files (*.*)|*.*"
openFileDialog1.FilterIndex = 2
openFileDialog1.RestoreDirectory = True

If openFileDialog1.ShowDialog() = System.Windows.Forms.DialogResult.OK Then
Try
Using sr As StreamReader = New StreamReader(openFileDialog1.FileName)
textbox1.Text = sr.ReadToEnd()
End Using
Catch E As Exception
Console.WriteLine(E.Message)
End Try
End If

保存的时候换成SaveFileDialog就好

Answer 2

首先创建一个文件流，然后读入文本信息，再然后编辑文本信息，没了