以下是完整的程序代码,根据要求输出每种结构助词出现的次数从少到多排列:
程序运行时,会打开名为"sefile104.txt"的文件,读取其中的文本内容,并对每个分词进行判断,如果是结构助词(即"的"、"地"、"得"三个单词),就记录它出现的次数。最后按要求输出每种结构助词出现的次数从少到多排列的结果。程序输出的格式为:每行输出一个结构助词和它出现的次数,结构助词左对齐,次数右对齐,宽度为5个字符,用减号字符"-"填充。
来义一个通最comb(sentence》,环两能是起一个英语却于导单同打况。然时输出新果幻于胎和阿小于2个此险出: 看与的学博小于等了2个。
i 1 #
import random
def comb(sentence):
#定义一个面数,参数为sentence
words=__(1)()#1把单调分制出末
print(“-“*6日)
if len(mords)==1(2) Len(words)=-2: #2如果句子中的单河小于2个,则不进行打,出“聚句的单调小于事于2个print(”原向的单词小于等于2个”)
else:
jumbte-[]while -__(3):#3对句子的单洞进行打乱site=-_(4)--(len(words))#4在句子中随机选取一个单调位置jumble.___(5)#5 肥随机取出的单调添加到Junblewords=(6》#6 把句于中剩杀的部再组备,注意切片时拉置都数如果是表达式夏同括号门)据起来5=_---(7)__-_(jumble)#7把单通用一个空格连接起来print(”句于打乱顺序后的单调组合为:\n”,s)
E
1f
__nane__==”__aain_:txt="The Beijing Organising Committe for the 2022 0lympic and paralyspic Winter Games 1s a public institutlon mith legal person status'
There are several errors in the code provided, and some parts are missing. Here's a corrected and completed version:
import random
def comb(sentence):
# Define a function with parameter "sentence"
words = sentence.split() # Split the sentence into words
print("-" * 6) # Print a separator line
Example usage:
sentence = "The Beijing Organising Committee for the 2022 Olympic and Paralympic Winter Games is a public institution with legal person status."
comb(sentence)
Note: The above code defines a function "comb" that shuffles the words in a sentence if there are more than two words. The function takes a string parameter "sentence". The example usage shows how to call the function with a sample sentence.
用智脑给你回答 的不知道准不准,我也不是程序员,仅供参考。