请大家帮忙用C语言编写一个四则运算程序

Question

这个是我们老师给我们留的期中作业，如果这个过不了，很可能我会挂科。所以拜托了。
老师的要求，进入界面的时候要弹出，欢迎光临我的C语言四则运算程序，之后会弹出请选择加减乘除，然后当你选择之后会自动跳出符合这个条件的一道题，如果错了会弹出回答错误，正确答案是。。。回答正确会问你，请问您想继续进行这个运算还是重新选择其他运算还是退出程序？，您就可以进行选择，总之如果选则运算就是不要一下子就结束程序要循环做，如果选择结束程序就会弹出，您做了几道题，错了几道题，正确率是多少。欢迎再来进行我的四则运算程序。总之老师的要求好复杂啊。我做不来，而且今天是6.2，请各位在6.3，最迟在6.4给我答案。再次拜托！
悬赏我会很高，我知道达人大虾不会在乎这个，希望各位可以帮帮我这个刚刚步入C语言的学子。如果做不来这个程序，可以把自己能做的分部程序写给我。谢谢啦！
我的C语言只学到了谭浩强第三版的第10章，所以太高深的代码我看不懂，老师一看就知道我怎么做的！

Answer 1

~~rand()%100用来产生0~100以内的随机数，不能每次都存入一样的数吧，所以用随机数好些，。。，，我学的也是谭浩强的，没有rand（）用于产生随机数，cystem(“pause”)用于暂停，相当于getchar()或getch（）,cystem("cls")用于清屏，可以去掉，这些东西都是我百度上百得。，。呵呵谭浩强书上确实没有这些东西。。
把问题先想清楚是一种很好的习惯，，呵呵
/* Note:Your choice is C IDE */
#include "stdio.h"
#include"windows.h"
int right=0,wrong=0;
void add()
{
int a,b,c;
a=rand()%100;
b=rand()%100;
printf("请回答:%d+%d=",a,b);
scanf("%d",&c);
if(a+b!=c){printf("回答错误\n");wrong++;}
else {printf("回答正确\n");right++;}
}
void minu()
{
int a,b,c;
a=rand()%100;
b=rand()%100;
printf("请回答:%d-%d=",a,b);
scanf("%d",&c);
if(a-b!=c){printf("回答错误\n");wrong++;}
else {printf("回答正确\n");right++;}
}
void mul()
{
int a,b,c;
a=rand()%100;
b=rand()%100;
printf("请回答:%d*%d=",a,b);
scanf("%d",&c);
if(a*b!=c){printf("回答错误\n");wrong++;}
else {printf("回答正确\n");right++;}
}
void di()
{
int a,b,c;
a=rand()%100;
b=rand()%100;
printf("请回答:%d/%d=",a,b);
scanf("%d",&c);
if(a/b!=c){printf("回答错误\n");wrong++;}
else {printf("回答正确\n");right++;}
}
void main()
{
int choise,con=0;

printf("\n\n\t\t欢迎光临我的C语言四则运算程序\n");
system("pause");
system("cls");
while(1)
{
printf("\n\n\t\t请选择:\n加(输入1)\n减(输入2)\n乘(输入3)\n除(输入4)\n");
if(con==0)scanf("%d",&choise);
switch(choise)
{
case 1:add();break;
case 2:minu();break;
case 3:mul();break;
case 4:di();break;

}
printf("请问您想继续进行这个运算还是重新选择其他运算还是退出程序？\n继续(输入1)，重新(输入2)，退出(输入3)");
scanf("%d",&con);
if(con==1)con=1;
if(con==2)con=0;
if(con==3)break;
}
printf("您总做了%d个题，正确%d的道，错误%d道！\n",right+wrong,right,wrong);
system("pause");
}
编译器不同可能不能运行，这是通用的VC6.0的编译器。另外，采用了 100之内的随机数做的题目

Answer 2

你就用楼下的程序吧！！

/*** 一共包含四个文件 *************
| Symbol.h
| Stack.h
| Expression.h
| Expression.c
| 这里的代码考虑到通用性，对代码的可
| 重用性作了细致的考虑，略显冗余，核心算法:
| Expression.h里的函数STATUS EvaluateExpression(float*fResult,char*strExpression)
**********************************/
// --Expression.c
#include "Expression.h"

extern EXPRESSION_DEBUG;

STATUS EvaluateExpression(float*,char*);
void Usage(char *);
int HandleOptions(int,char **);

int main(int argc,char*argv[ ])
{
char strLine[30]={0};
float fResult=0;

/* handle the program options */
HandleOptions(argc,argv);
fprintf(stderr,"Input cls to clear the screen\n");
fprintf(stderr," debug to show stack change\n");
fprintf(stderr," nodebug to show no stack change\n");
fprintf(stderr," end to exit\n");
while(TRUE)
{
printf("Input:\n");
gets(strLine);
if(!strcmp(strLine,"end"))
break;
if(!strcmp(strLine,"cls")) {
system("cls");
continue;
}
if(!strcmp(strLine,"debug")){
EXPRESSION_DEBUG=TRUE;
continue;
}
if(!strcmp(strLine,"nodebug")){
EXPRESSION_DEBUG=FALSE;
continue;
}
EvaluateExpression(&fResult,strLine);
printf("Ans=%f\n",fResult);
}
return OK;

}

void Usage(char *programName)
{
fprintf(stderr,"%s usage:%s [-d][-h/?]\n",programName,programName);
fprintf(stderr,"-d Test program, calculate expression and\n");
fprintf(stderr," see changes in the stack at the same time.\n");
exit(OK);
}

/* returns the index of the first argument that is not an option; i.e.
does not start with a dash or a slash
*/
int HandleOptions(int argc,char *argv[])
{
int i,firstnonoption=0;

for (i=1; i< argc;i++) {
if (argv[i][0] == '/' || argv[i][0] == '-') {
switch (argv[i][1]) {
/* An argument -? means help is requested */
case '?':
case 'h':
case 'H':
Usage(argv[0]);
break;
case 'd':
case 'D':
EXPRESSION_DEBUG=TRUE;
break;
default:
fprintf(stderr,"unknown option %s\n",argv[i]);
break;
}
}
else {
firstnonoption = i;
break;
}
}
return firstnonoption;
}

//--Symbol.h
//--symbol.h - definitions/declarations for symbols used by other C Header files

#ifndef SYMBOL_H
#define SYMBOL_H

#define STACK_H
#define TRUE 1
#define OK 1
#define YES 1
#define FALSE 0
#define ERROR 0
#define NO 0
#define OVERFLOW -1
#ifndef NULL
#define NULL 0
#endif

typedef unsigned int UINT;
typedef int STATUS;
typedef int BOOL;

#endif /*SYMBOL_H*/

//--stack.h - definitions/declarations for stack operation

#ifndef STACK_H
#define STACK_H

#include "Symbol.h"
#include <malloc.h>
#include <stdio.h>
#include <conio.h>
#include <stdlib.h>
#include <string.h>

#define S_CHAR 1
#define S_SHORT 2
#define S_INT 3
#define S_FLOAT 4
#define S_DOUBLE 5

//-- Stack.h
typedef struct tagNode
{
void*pData;
struct tagNode*pNext;
}Node,*PNode;
typedef struct tagStack
{
UINT uType;
/*1 char
*2 short/short int
*3 int
*4 float
*5 double
*/
UINT uLength;
struct tagNode*pFirst;
struct tagNode*pTop;
}Stack,*PStack;

STATUS InitStack(PStack pStack,UINT uType)
{
pStack->uType=uType;
pStack->uLength=0;
pStack->pFirst=pStack->pTop=NULL;
return OK;
}

STATUS ShowStack(PStack pStack)
{
PNode pNode=pStack->pFirst;
while(pNode)
{
switch(pStack->uType)
{
case S_CHAR: // char
printf("%c ",*(char*)(pNode->pData));break;
case S_FLOAT: // float
printf("%-4.1f ",*(float*)(pNode->pData));
}
pNode=pNode->pNext;
}
putchar(10);
return OK;
}

STATUS Push(PStack pStack,void*pData)
{
PNode pNode=(PNode)malloc(sizeof(Node));
if(!pNode)
{
printf("\nmalloc error!\n");
fflush(stdin);
getch();
exit(ERROR);
}
if(pStack->uType==1)
{
pNode->pData=(char*)malloc(sizeof(char));
*(char*)(pNode->pData)=*(char*)pData;
}
else if(pStack->uType==3)
{
pNode->pData=(int*)malloc(sizeof(int));
pNode->pData=(int*)malloc(sizeof(int));
*(int*)(pNode->pData)=*(int*)pData;
}
else if(pStack->uType==4)
{
pNode->pData=(float*)malloc(sizeof(float));
pNode->pData=(float*)malloc(sizeof(float));
*(float*)(pNode->pData)=*(float*)pData;
}
else if(pStack->uType==5)
{
pNode->pData=(double*)malloc(sizeof(double));
pNode->pData=(double*)malloc(sizeof(double));
*(double*)(pNode->pData)=*(double*)pData;
}
pNode->pNext=NULL;
if(!pStack->pTop)
pStack->pTop=pStack->pFirst=pNode;
else
{
pStack->pTop->pNext=pNode;
pStack->pTop=pNode;
}
pStack->uLength++;
return OK;
}

STATUS Pop(PStack pStack,void*pData)
{
PNode pPre=pStack->pFirst;
if(pStack->pTop!=pStack->pFirst)
while(pPre->pNext!=pStack->pTop)
pPre=pPre->pNext;
else
pPre=NULL;
if(pStack->uType==1)
*(char*)(pData)=*(char*)(pStack->pTop->pData);
else if(pStack->uType==3)
*(int*)(pData)=*(int*)(pStack->pTop->pData);
else if(pStack->uType==4)
*(float*)(pData)=*(float*)(pStack->pTop->pData);
else if(pStack->uType==5)
*(double*)(pData)=*(double*)(pStack->pTop->pData);
free(pStack->pTop->pData);
free(pStack->pTop);
pStack->pTop=pPre;
if(pPre)
pStack->pTop->pNext=NULL;
else
pStack->pFirst=NULL;
pStack->uLength--;
return OK;
}

STATUS GetTop(PStack pStack,void*pData)
{
if(pStack->uType==1)
*(char*)(pData)=*(char*)(pStack->pTop->pData);
else if(pStack->uType==3)
*(int*)(pData)=*(int*)(pStack->pTop->pData);
else if(pStack->uType==4)
*(float*)(pData)=*(float*)(pStack->pTop->pData);
else if(pStack->uType==5)
*(double*)(pData)=*(double*)(pStack->pTop->pData);
return OK;
}
STATUS DestroyStack(PStack pStack)
{
PNode pPre1,pPre2;
pPre1=pPre2=pStack->pFirst;
while(pPre1)
{
pPre1=pPre1->pNext;
free(pPre2->pData);
free(pPre2);
pPre2=pPre1;
}
pStack->pFirst=pStack->pTop=NULL;
pStack->uLength=0;
return OK;
}

#endif /* STACK_H */

//--Expresson.h

#ifndef EXPRESSION_H
#define EXPRESSION_H

#include "Stack.h"

typedef struct tagOptr
{
char cOptr;
UINT uPriority;
}Optr,*POptr;

BOOL EXPRESSION_DEBUG=FALSE;
Optr pOptr[8]={{0,7},{')',1},{'*',2},{'/',2},{'+',3},{'-',3},{'(',4},{'#',4}};
STATUS Operate(float*fTemp3,float fTemp1,char theta,float fTemp2)
{
switch(theta)
{
case '+':*fTemp3=fTemp1+fTemp2;break;
case '-':*fTemp3=fTemp1-fTemp2;break;
case '*':*fTemp3=fTemp1*fTemp2;break;
case '/':
if(fTemp2!=0)
*fTemp3=fTemp1/fTemp2;
else
{
printf("\n0 can not be divisor!\n\nPress any key to continue...\n");
fflush(stdin);
getch();
exit(ERROR);
}// else
break;
}
return OK;
}

int Precede(char cOptrTop,char cChar)
{
UINT i,j;
if(cOptrTop=='#'&&cChar=='#')
return 0;
if(cChar=='(')
return -1;
if(cChar==')')
if(cOptrTop=='(')
return 0;
else
return 1;
for(i=1;i<=pOptr[0].uPriority;i++)
if(pOptr[i].cOptr==cOptrTop)
{
i=pOptr[i].uPriority;
break;
}
for(j=1;j<=pOptr[0].uPriority;j++)
if(pOptr[j].cOptr==cChar)
{
j=pOptr[j].uPriority;
break;
}
if(i<=j)
return 1;
else
return -1;
return -2;
}

STATUS IsIn(char cChar)
{
if(cChar>='0'&&cChar<='9'||cChar=='.')
return YES;
return NO;
}

STATUS Debug(PStack stackOptr,PStack stackOpnd,char*strExpression,int i)
{
// --debug
if(EXPRESSION_DEBUG)
{
printf("-------------------------------\n");
printf("%s\n",strExpression);
printf("Optr:");
ShowStack(stackOptr);
printf("Opnd:");
ShowStack(stackOpnd);
}
return OK;
}
STATUS EvaluateExpression(float*fResult,char*strExpression)
{
char cChar='#',cOptrTop=0,theta=0;
float fTemp1,fTemp2,fTemp3,fTemp4;
int i=0,iTemp;
Stack stackOptr,stackOpnd;
InitStack(&stackOptr,S_CHAR);
InitStack(&stackOpnd,S_FLOAT);
Push(&stackOptr,&cChar);
GetTop(&stackOptr,&cOptrTop);
strcat(strExpression,"#");
if(strExpression[0]=='-'){
fTemp1=0;
Push(&stackOpnd,&fTemp1);
}
cChar=strExpression[0];
while(cChar!='#'||cOptrTop!='#')
{
Debug(&stackOptr,&stackOpnd,strExpression,i);
if(IsIn(cChar))
{
fTemp1=0;
fTemp3=10;
fTemp4=1;
while(IsIn(cChar))
{
if(cChar=='.'){
fTemp3=1;
cChar=strExpression[++i];
continue;
}
fTemp2=(float)(cChar-'0');
if(fTemp3==1)
{
iTemp=i;
while(IsIn(strExpression[i])){
fTemp2/=10;
i++;
}
i=iTemp;
}
fTemp1=fTemp1*fTemp3+fTemp2;
cChar=strExpression[++i];
}
Push(&stackOpnd,&fTemp1);
}
else
{
switch(Precede(cOptrTop,cChar))
{
case -1:Push(&stackOptr,&cChar);cChar=strExpression[++i];break;
case 0:Pop(&stackOptr,&cChar);cChar=strExpression[++i];break;
case 1:
Pop(&stackOptr,&theta);
Pop(&stackOpnd,&fTemp2);Pop(&stackOpnd,&fTemp1);
Operate(&fTemp3,fTemp1,theta,fTemp2);
Push(&stackOpnd,&fTemp3);
break;
}// switch
GetTop(&stackOptr,&cOptrTop);
}// else
}// while
Pop(&stackOptr,&cChar);
Debug(&stackOptr,&stackOpnd,strExpression,i);
GetTop(&stackOpnd,fResult);
DestroyStack(&stackOptr);
DestroyStack(&stackOpnd);
return OK;
}// EvaluateExpression

#endif // EXPRESSION_H

参考资料：http://zhidao.baidu.com/question/56467676.html

Answer 3

个人认为 不难做 可惜很烦 这里一般没人会花力气为了分写代码的 除非是复制 自己努力下？ 有不懂的可以问，但是找人写代码恐怕这里很少人有写
你要求太具体，没法复制就更没人给代码了 呵呵

Answer 4

论坛里很多阿