求解答这道物理化学题目

Question

详细公式要写，谢谢大家

Answer 1

1
比较下面两式：
ln(P) = 24.62-4885/T
ln(P) = C-ΔvH/(RT)
有
4885/T = ΔvH/(RT)
即
ΔvH = 4885*R
又
R = 8.314J/(mol*K)
故
ΔvH = 4885*R = 4885*8.314 = 40614J/(mol) = 40.614(kJ)/(mol)

2
当饱和蒸气压为101.325kPa时，所对应的温度称为该液体的正常沸点。
由
ln(P) = 24.62-4885/T
有
T = 4885/(24.62-ln(P))
故
T = 4885/(24.62-ln(101325)) = 373.0742 K

3
巳知 P = 60 kPa = 60000 Pa
而
T = 4885/(24.62-ln(P))
故
T = 4885/(24.62-ln(60000)) = 358.7190 K

4
巳知 T = 399
而
ln(P) = 24.62-4885/T
故
ln(P) = 24.62-4885/399 = 12.3769
所以，
P = e^(12.3769) = 237257.18 Pa = 237.26 kPa