解ï¼ï¼1ï¼æ±å¯¼ å¾y'=6x^2-6x
令y'=0 å¾x=+ -1
y(-1)=-5 y(1)=-1 y(4)=80
æ
æ大å¼80 æå°å¼-5
ï¼2ï¼è®¾â(1ï¼x)=tï¼å¾ï¼x=1ï¼t²ã
å 为xâ[ï¼5,1],åtâ[â6,0]
ä¸y=(1ï¼t²)ï¼t
=ï¼t²ï¼tï¼1
=ï¼[tï¼(1/2)]²ï¼(5/4),å
¶ä¸tâ[â6,0]
ç»åäºæ¬¡å½æ°å¾å,å¾ï¼
yçæ大å¼æ¯5/4ï¼æå°å¼æ¯ï¼5ï¼â6
ï¼3ï¼xå¨[0,Ï/2)å
,å tanxå±äº[0,+â)
y=2tanx-(tanx)^2
=-(tanx-1)²+1
ç±æ¤å¯çåºè¯¥å½æ°ä¸ºå¼å£åä¸çäºæ¬¡å½æ°ï¼ææ大å¼ï¼æ æå°å¼
-(tanx-1)²+1çæ大å¼å¨tanx=1æ¶åå¾ï¼æ大å¼ä¸º1
-(tanx-1)²+1æ æå°å¼ï¼å¼åæ¯(-â,1]
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