HAc<==>H+ + Ac-
Ka=[H+]*[Ac-]/[HAc]
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pH=pKa + lg[Ac-]/[HAc]=pKa + lgn(Ac-)/(HAc)=4.74+ lg (100)/(100)=4.74
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¥ï¼1ï¼1.0mL6.0mol/LHCLå
pH=pKa + lg[Ac-]/[HAc]=pKa + lgn(Ac-)/(HAc)=4.74+ lg (100-6)/(100+6)=4.69
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