数学函数f(x)=x2+1的C++语言的编程，求高手啊

Question

如题所述

Answer 1

#include<iostream>
using namespace std;
void main()
{
bool bl=true;
while(bl)
{
cout<<"请输入X的值："<<endl;
double x,y;
cin>>x;
y=2*x+1;
cout<<"当x="<<x<<"时"<<endl<<"y=2x+1="<<y<<endl;
cout<<"按“0”结束计算，按1继续！"<<endl;
int key;
cin>>key;
if(key==0){bl=false;}
else continue;
}
cin.get();
}

Answer 2

#include <iostream>
using namespace std;

int main()
{
long x, fx;
cin >> x ;
fx = x * x + 1;
cout << "f(x)值为" << fx << endl;
system("pause");
return 0;
}

Answer 3

#include <iostream>
using namespace std;

double f(double); // 函数声明

void main()
{
double x;
cout << " x = ";
cin >> x;

cout << "f(x) = ";
cout << f(x) << endl; //函数调用
}

double f(double x) //函数定义
{
return x * x + 1;
}

Answer 4

#include <iostream>
using namespace std;
int main()
{
int x;
cin>>x;
cout<<x*x+1;
}

Answer 5

# include<stdio.h>
int main()
{
int x;
double sum;
printf("Enter x: ");
scanf("%d",&x);
sum = x * 2 + 1;
printf("f(x) = %lf \n",sum);
return 0;
}

Answer 6

int Funcation(int x)
{
return 2*x + 1;
}