第1个回答 推荐于2016-04-02
这个不难,代码如下:
command1的代码:
Private Sub Command1_Click()
Dim s1 As String
Dim a() As String
Dim i As Integer
Open "txt地址" For Input As #1
While Not EOF(1)
Line Input #1, s
s1 = s1 & s & IIf(EOF(1), "", vbCrLf)
Wend
Close #1
a() = Split(s1, vbCrLf)
a(List1.ListIndex) = ""
Open "txt地址" For Output As #1
For i = 0 To UBound(a)
Print #1, a(i) & vbCrLf
Next i
Close #1
MsgBox "删除成功!"
End Sub本回答被提问者采纳