1. 24.4gNaOH 24.4/40=0.61mol
C(NaOH )=0.61/0.1=6.1mol/L
2. m(溶液ï¼=100*1.22=122å
NaOHç
è´¨éåæ°=24.4/122=20%
3.å1/10ï¼æµåº¦ï¼å¯åº¦ä¸åï¼è´¨éãç©è´¨çéå为1/10
ä»è¯¥æº¶æ¶²ä¸ååº10mL,å
¶ä¸NaOHç
ç©è´¨çéæµåº¦ä¸º_6.1mol/L_____,BaIHçè´¨éåæ°ä¸º_20%____,溶液çå¯åº¦ä¸º__1.22g/ml____,
å«NaOHçè´¨é为__2.44å
___,
å«NaOHçç©è´¨çé为__0.061æ©å°_