(5)
y=∫(0->2x) e^(t^2)/sin(3t) dt
y'
= [e^((2x)^2)/sin(3(2x)) ] .(2x)'
= [e^(4x^2)/sin(6x) ] .(2)
=2e^(4x^2)/sin(6x)
ans: C
(1)
y=√(x^2-1) / ln(1+x)
x^2 -1≥0
(x-1)(x+1)≥0
x≤-1 or x≥1 (1)
and
1+x > 1
x> 0 (2)
定义域
(1) and (2)
"x≤-1 or x≥1" and x>0
x≥1
定义域 = [1, +无穷)