C++题目：从键盘上输入10个实数，并求出这10个数之和及平均值。用循环语句实现，写出程序。谢谢

Question

a[ ] namespace 我还没学到 。。。

Answer 1

#include <iostream.h>
void main()
{
int i;
float sum,a[10]={0};
sum=0;
cout<<"请输入10个实数，实数之间以空格隔开!\n";
for(i=0;i<10;i++)
{
cin>>a[i];
sum=sum+a[i];
}
cout<<"这10个实数的和为"<<sum<<" \n平均数为"<<sum/10.0<<"\n";
}

Answer 2

#include <iostream>
using namespace std;

int main ()
{
double temp;
double sum = 0;
for (int i = 0; i < 10; i++) {
cin >> temp;
sum += temp;
}
cout << sum << endl; //这10个数的和
cout << sum/10; //平均数
system ("pause");
return 0;
}本回答被提问者采纳

Answer 3

#include<iostream>
using namespace std;
int main()
{
int *a=new int[10],sum=0,i=0;
while(i<10)
{
cin>>*a;
sum+=*a++;
i++;
}
cout<<"the sum is "<<sum<<"the average is "<<sum/10<<endl;
delete []a;
return 0;
}本回答被网友采纳

Answer 4

#include <iostream>

using namespace std;

int main()
{
int ai[10];
int count=0;

cout<<"please input 10 number:"<<endl;
for(int i=0;i<10;i++)
{
cin>>ai[i];
}
for(int i=0;i<10;i++)
{
count += ai[i];
}

cout<<"总和："<<count<<endl;
cout<<"平均："<<(float)(count/10)<<endl;

return 0;
}

Answer 5

#include<stdio.h>
void main()
{
int i,n,sum=0;
float ave=0.0;
printf("请输入十个数：\n");
for(i=0;i<10;i++)
{scanf("%d",&n);
sum+=n;}
ave=sum/10;
printf("十个数的和是：%d\n十个数的平均值是：%f\n",sum,ave);
}