1+1=2怎么用C语言编程

Question

如题所述

Answer 1

c程序代码内容如下：
# include <stdio.h>
main()
{
int a,b,c;
printf("请输入两个整数,中间以空格隔开:\n");
scanf("%d%d",&a,&b);
c=a+b;
printf("这两个数的和是:a+b=%d\n",c);
}
然后按提示输入“1 1”就会显示：“a+b=2”
编程完成！

Answer 2

#include<stdio.h>
void main()
{
int a=1, b=1, c;
c=a+b;
printf("c",&d);
}本回答被提问者采纳

Answer 3

#include "stdio.h"
int return_1(int);
int result_2(int,int);

int return_1(int x){
x=5;
return x/5}

int result_2(int x,int y){
return (2*x+2*y)/2;
}

int main(){
int b;
b=2;
printf("1+1=");
b=((b+1)*2-5)/1;
int c;
c=b;
printf("%d\n",result_2(b,c));

return 0;}

Answer 4

#include "stdio.h"
main()
{
printf("1+1=2");
}

Answer 5

#include<stdio.h>
main()
{
int a;
int b;
int c;
a=4;b=2;
c=a+b;
printf("%d",c\n);
}