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Z=U/I=220/4.2=52.38Ω
P=I^2*R=325ï¼
解åºR=18.42Ω
Xc=â(52.38^2-18.42^2)=49Ω
C=1/(ÏXc)=1/(314*49)=65uF
é»æä¸è§xè½´18.42Ωï¼æè¾¹52.38Ωï¼Î±è§åº¦arccos18.42/52.38=-69.4º(è´è§åº¦è¡¨ç¤ºä¸ºå®¹æ§è´è½½ï¼ä¸åï¼
çµåä¸è§å½¢åºè¾¹ä¸ºxè½´ï¼é¿åº¦18.42*4.2=77.4Vï¼æè¾¹220Vï¼ç¸ä½è§Î±=arccos77.4/220=-69.4º
åçä¸è§å½¢çåºè¾¹ä¸ºxè½´ï¼é¿åº¦325Wï¼æè¾¹229*4.2=924VAï¼ç¸ä½è§Î±=arccos325/924=-69.4º
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