第1个回答 2010-06-17
发生三种类型的反应,分别是取代(醚化)反应,消去反应,酯化反应;
发生取代反应,生成醚类物质有二甲醚、二丙醚、甲丙醚;
2CH3OH→CH3OCH3 + H2O
2C3H7OH→C3H7OC3H7 + H2O
CH3OH + C3H7OH→CH3OC3H7 H2O
发生消去反应可以得到丙烯;
C3H7OH→ CH2=CHCH3↑ + H2O
将硫酸看成H—SO3H,与醇类发生酯化,可以得到硫酸氢甲酯、硫酸二甲酯、硫酸氢丙酯、硫酸二丙酯。
H2SO4 + CH3OH → CH3OSO3H + H2O
H2SO4 + 2CH3OH → CH3OSO2CH3 + 2H2O
H2SO4 + C3H7OH → C3H7OSO3H + H2O
H2SO4 + 2CH3OH → C3H7OSO2C3H7 + 2H2O
第2个回答 2010-06-17
甲醚、乙醚、甲乙醚,乙烯,硫酸乙酯,5种
第3个回答 2010-06-17
(1)最基础的是9种,估计你说的没有最后两种
丙烯、二甲醚、二丙醚、甲丙醚、硫酸二甲酯、硫酸二丙酯、硫酸甲丙酯、硫酸氢甲酯、硫酸氢丙酯
(2)基础的是4种
乙烯、乙醚、硫酸二乙酯、硫酸氢乙酯
事实上产物很多样,但主要是这些。
第4个回答 2010-06-17
1\
CH3CH=CH2
CH3CH2CH2OCH2CH2CH3
CH3OCH3
CH3CH2CH2OCH3
(CH3)2-CH-O-CH-(CH3)2
(CH3)2-CH-O-CH3
2\
CH3CH=CH2
CH2=CH2
CH3CH2CH2OCH2CH3
CH3CH2CH2OCH2CH2CH3
CH3CH2OCH2CH3
(CH3)2-CH-O-CH-(CH3)2
(CH3)2-CH-O-CH2CH3
第5个回答 2010-06-18
1\最多可得7种有机物
CH3CH=CH2
CH3CH2CH2OCH2CH2CH3
CH3OCH3
CH3CH2CH2OCH3
(CH3)2-CH-O-CH-(CH3)2
(CH3)2-CH-O-CH3
(CH3)2-CH-O-CH2CH2CH3
2\
CH3CH=CH2
CH2=CH2
CH3CH2CH2OCH2CH3
CH3CH2CH2OCH2CH2CH3
CH3CH2OCH2CH3
(CH3)2-CH-O-CH-(CH3)2
(CH3)2-CH-O-CH2CH3
(CH3)2-CH-O-CH2CH2CH3