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åçç§,çææ åµä¸4.48Läºæ°§å碳å1.8gæ°´ï¼æ以å¯ä»¥è®¾ææºç©åå¦å¼ä¸ºCnHmOxã
CnHm Ox + ï¼n+m/4-x/2ï¼O2 = n CO2 + m/2 H2O
1 n m/2
4.48/22.4=0.2mol 1.8/18=0.1mol
æä»¥ï¼ n:m/2=0.2:0.1 n:m=1:1 n=m
2.6g
0.2molCO2å«ç¢³çè´¨é=2.4å
ï¼0.1molæ°´å«æ°¢çè´¨é=0.2å
ï¼2.4+0.2=2.6å
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