C语言，输入一个数，判断它是奇数还是偶数，如果是偶数则进一步判断它是否为4的倍数

Question

输入一个数，判断它是奇数还是偶数，如果是偶数则进一步判断它是否为4的倍数

Answer 1

#include "stdio.h"

int main()

{

       int n;

       scanf("%d",&n);

       if(n%2==1)

           printf("%d是奇数!\n",n);

       else if(n%4==0)

           printf("%d是偶数而且是4的倍数!\n",n);

      else

           printf("%d是偶数，但不是4的倍数!\n",n);

 

}

Answer 2

#include<stdio.h>
main()
{
unsigned char num;
printf("请输入一个数：\n");
scanf("%d",&num);
if(num%2==1)
printf("这是奇数\n");
else
{
if(num%4==0)
printf("是4的倍数\n");
else
printf("是2的倍数，但不是4的倍数\n");
}
}

Answer 3

#include<stdio.h>
int main()
{
    int a;
    scanf("%d",&a);
    if(a%2)
    {
        printf("是奇数。\n");
    }
    else
    {
        if(a%4==0)
            printf("是4的倍数\n");
    }
    return 0;
}

Answer 4

#include <stdio.h>

int main(void)
{
int num;

scanf("%d", &num);

if(!(num &0x01))
{
if(!(num &0x03))
{
printf("%d 是 4 的倍数！\n", num);
}
else
{
printf("%d 能被 2 整除,但不是 4 的倍数\n", num);
}
}
else
{
printf("%d 是奇数!\n", num);
}

return 0;
}

Answer 5

#include<stdio.h>
main()
{
unsigned char num;
printf("请输入一个数：\n");
scanf("%d",&num);
if(num%2==1)
printf("这是奇数\n");
else
{
if(num%4==0)
printf("是4的倍数\n");
else
printf("是2的倍数，但不是4的倍数\n");
}
}

Answer 6

#include<stdio.h>
int main()
{
    int a;
    scanf("%d",&a);
    if(a%2)
    {
        printf("是奇数。\n");
    }
    else
    {
        if(a%4==0)
            printf("是4的倍数\n");
    }
    return 0;
}

Answer 7

#include <stdio.h>

int main(void)
{
int num;

scanf("%d", &num);

if(!(num &0x01))
{
if(!(num &0x03))
{
printf("%d 是 4 的倍数！\n", num);
}
else
{
printf("%d 能被 2 整除,但不是 4 的倍数\n", num);
}
}
else
{
printf("%d 是奇数!\n", num);
}

return 0;
}