(C语言编程)键盘输入100个整数，计算并输出大于等于0的个数和平均值（保留2位小数）

Question

键盘输入100个整数，计算并输出大于等于0的个数和平均值（保留2位小数）

Answer 1

#inlude "stdio.h"int main(){
int sum=0,a[100],i,j;printf("请输入100个整数：\n");for(i=0;i<100;i++){ scanf("%d",&a[i]);sum+=a[i];}j=0;printf("大于等于0的数有：\n");for(i=0;i<100;i++) if(a[i]>=0){printf("%d\t",a[i]);if(j++>5){j=0;printf("\n");}}printf("平均数为：%.2f\n",(float)sum/100);}

Answer 2

#inlude "stdio.h"int main(){
int sum=0,a[100],i,j,count;count=0;printf("请输入100个整数：\n");for(i=0;i<100;i++){scanf("%d",&a[i]);if(a[i]>=0){sum+=a[i];count++;}}printf("大于等于0数有%d个：\n",count);printf("平均数为：%.2f\n",(float)sum/count);}本回答被网友采纳

Answer 3

#include <stdio.h>
#define N 100void main(void)
{
int num;
int i,count;
float avg;
for(avg = 0,count = i=0;i<N;i++)
{
scandf("%d", &num);
if(num >= 0)
{
count++;
avg += num;
}
}
avg /= count;
printf("%d %.2f", count, avg);
}

Answer 4

#include"stdio.h"
main()
{int i=0,a[10],num=0,n=0;</p><p> for(i=0;i<100;i++)<br> {<br> printf("inpit number:");<br> scanf("%d",&a[i]);<br> num+=a[i];<br> if(a[i]>=0) n++;<br> } printf("%d\t%.2f",n,(num/100.0));
getch();
}

Answer 5

#include<stdlib.h>
void main(){
int a[100],i,n;
float ave=0.0;
for(i=0;i<100;i++){
scanf("%d",&a[i]);
if(a[i]>=0){
n++;
ave+=a[i];
}
}
ave/=n;
printf("n=%d\tave=%.2f",n,ave);
getch();
}