谁能帮我修改一下这段简单的C语言代码？我想要实现 继续吗？yes or no的功能！

Question

#include "stdio.h"
void main()
{
int i,j,n;
char mon[12][100]={"January","February","March","April","May","June","July","August","September","October","November","December"};
char *p[12];
for(i=0;i<12;i++)
p[i]=mon[i];

while(j)
do
{
printf("请输入月份号:\n");
scanf("%d",&n);
if(n<=0||n>12)
{printf("月份输入错误\n");}
printf("%s",*(p+n-1));
printf("\n");

printf("还要继续吗？Y or N\n");
scanf("%c",&j);
if(j=='Y'||j=='y') j=1;
}

}/* 输入月份号,输出该月的英文月名。(要求用数组处理)*/

Answer 1

#include "stdio.h"
void main()
{
int i,j,n;
char mon[12][100]={"January","February","March","April","May","June","July","August","September","October","November","December"};
char *p[12];
for(i=0;i<12;i++)
p[i]=mon[i];

while(j) //do 去掉，你语法有点不熟练
{
printf("请输入月份号:\n");
scanf("%d",&n);
if(n<=0||n>12)
{printf("月份输入错误\n");}
printf("%s",*(p+n-1));
printf("\n");
getchar(); //这里加个，接收回车键
printf("还要继续吗？Y or N\n");
scanf("%c",&j);
if(j=='Y'||j=='y') j=1;
else
j=0; //这里
}

}追问

最后一个注释“这里”似乎欲言又止啊，你想说啥？

追答

就是如果不是输入Y，y 那就设置 j=0；就是退出标记

追问

还有，我这边输入y之后就无法继续了（无法响应），故意输入13后也是……用你的编译器试试！

追答

把int j;改成 char j;就可以了，你输入13不满足，要强制性退出来，在
if(n12)
{printf("月份输入错误\n");
break; }//加个break;就可以

Answer 2

初学者，不过试过了能按你的意思运行。。。
#include<stdio.h>
#include<stdlib.h>
#include<conio.h>
main()
{
int i,n,j;
char ch;
char mon[12][100]={"January","February","March","April","May","June","July","August","September","October","November","December"};
char *p[12];
for(i=0;i<12;i++)
p[i]=mon[i];

do
{
j=0;
printf("请输入月份号:\n");
scanf("%d",&n);
if(n<=0||n>12)
{
printf("月份输入错误\n");
}

printf("%s",*(p+n-1));
printf("\n");
printf("还要继续吗？Y or N\n");
ch=getch();
putch(ch);
if(ch=='Y'||ch=='y')
j=1;

}
while(j);
}追问

ch=getch();
putch(ch); ？？

请问为何要加个putch(ch);只起到了输出字符的作用吧？

追答

额，putch可以显示在运行窗口的，如果没有这条语句，前面的会接收到输入了字符，但显示屏没有的，我用那个C语言编译运行过了。。。

追问

一定要ch=getch();？ch=getchar();好像不行啊，你那头试试！