第1个回答 2013-06-10
x+a%3*(int)(x+y)%2/4运算顺序为:a%3a%3*(int)(x+y)a%3*(int)(x+y)%2a%3*(int)(x+y)%2/4x+a%3*(int)(x+y)%2/4*%/为同级,按从左到右
第2个回答 2013-06-10
#include<stdio.h>void main(){ float x=2.5,a=7,y=4.7,z; z=x+a%3*(int)(x+y)%2/4;printf("z=%f\n",z);}
第4个回答 2015-11-28
#include<stdio.h>
void main()
{
int x,a,y,z;
x=2.5;
a=7;
y=4.7;
z=x+a%3*(int)(x+y)%2/4;
printf("z=%d\n",z);
}本回答被网友采纳