#include<stdio.h> int main() { int i,sum,a[10] = { 53,78,93,45,41,34,12,90,26,75}; for (i = 0; i < 10; i++) if (a[i] % 2 == 0) sum += a[i] * a[i]; printf("偶数和为:%d",sum); } 祝你愉快!本回答被网友采纳
第2个回答 2013-06-26
int a[]={53,78,93,45,41,34,12,90,26,75};
int B[]=""; int j=0; int cnt=0; int sum=0; for(i=0;i++;i<10) { if(A(i)%2==0) { B(cnt)=A(i);