C语言怎么实现任意两个数的四则运算

Question

如题所述

Answer 1

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32

#include<stdio.h>

int main(void)
{
int a, b;
char c;
printf("请输入两个数:");
scanf("%d %d", &a, &b);
getchar();
printf("请输入你需要的运算法则：");
scanf("%c",&c);

switch (c)
{
case '+':
printf("%d+%d = %d", a, b, a+b);
break;
case '-':
printf("%d-%d = %d", a, b, a-b);
break;
case '*':
printf("%d*%d = %d", a, b, a*b);
break;
case '/':
printf("%d/%d = %d", a, b, a/b);
break;
default:
printf("输入的符号有错！");
break;
}
return 0;