Python随机产生10个70-100的数并输出,找出其中的最小值及其第一次出现的位置？

Question

如题所述

Answer 1

import random
random_numbers = []
for i in range(10):
random_numbers.append(random.randint(70, 100))
min_value = min(random_numbers)
min_index = random_numbers.index(min_value)
print("随机数列表：", random_numbers)
print("最小值：", min_value)
print("最小值的位置：", min_index)

Answer 2

import random;
arr=random.sample([j for j in range(70,101)],10)#random.sample(list,countRandom);
arra=[random.randint(70,100) for j in range(10)]#random.randint(start_number,end_number);

print(f"{arr=}\n{min(arr)=}\n{arr.index(min(arr))=}")
print(f"{arra=}\n{min(arra)=}\n{arra.index(min(arra))=}")