如题所述
过程?
(1),消元得C1:y^2=4x,∵ρcos(θ+Π/4)=✔2/2∴✔2/2ρcosθ-✔2/2ρsinθ=✔2/2∴ρcosθ-ρsinθ=1∴x-y=1即y=x-1(2)交点为A(X1,Y1),B(X2,Y2)直线y=x-1的参数方程为{x=3-t✔2/2{y=2+t✔2/2将其带入C1得:t^2-8✔2t-16=0∴t1·t2=-16由t的几何意义知:|PEIlPF|=It1I·It2I=It1·t2I=16故:|PEIlPF|=16