求大神帮忙把Java代码写出来

Question

如题所述

Answer 1

public static void main(String[] args) {
String[] name={"T恤","网球鞋","网球拍"};
String[] money={"￥245”,"￥570“,“￥320”};
System.out.println("*******************************");
System.out.println("请选择购买的商品编号:\n");
System.out.println("1.T恤 2.网球鞋 3.网球拍");
System.out.println("*******************************\n");
Scanner input=new Scanner(System.in);
Boolean type=true;
while (type) {
System.out.println("请输入商品编号");
int no=input.nextInt();
System.out.println(name[no]+"\t"+money[no]+"\n");
System.out.println("是否继续?(y/n)");
if (input.next().equals("n")) {
type=false;
}
}
System.out.println("程序结束!");
}

Answer 2

你好，我的代码可能不是最直观的，但是Java是一门面向对象的语言，应该用面向对象的思想写，这点很重要。

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class Main {
public static void main(String[] args) throws IOException{
Product[] p = { new Product(1,"T恤",245),
new Product(2,"网球鞋",570),
new Product(3,"网球拍",320)
  };
System.out.println("1.T恤\t2.网球鞋\t3.网球拍\n................................");
while(true){
System.out.print("请输入商品编号：");
BufferedReader input = new BufferedReader(new InputStreamReader(System.in));
int i = Integer.parseInt(input.readLine());
if(i==1||i==2||i==3)
System.out.println(p[i-1].name + "\t￥" + p[i-1].price);
System.out.print("是否继续（y/n）");
String s = input.readLine();
if(s.equals("n")){
System.out.println("程序结束");
break;
}
}
}
}
class Product{
int num;
String name;
float price;

Product(int num, String name, float price){
this.num = num;
this.name = name;
this.price = price;
}
}

运行结果：

希望可以帮到你！

Answer 3

import java.util.Scanner;

public class Price {
public static void main(String[] args) {
int[] prices = {245, 570, 320};
Scanner scanner = new Scanner(System.in);
String line;
System.out.print("type a number or n:");
while((line = scanner.nextLine()) != "n") {
int no = Integer.parseInt(line);
System.out.println("price is " + prices[no - 1]);
System.out.print("type a number or n:");
}
System.out.println("exit normally!");
}
}