分别求出数组中所有奇数之和以及所有偶数之和。答:int i;even=0;odd=0;for(i=0;i<n;i++){ if(a[i]%2==0)even=*even+a[i];else odd=*odd+a[i];} }void main(){ int a[N]={1,10,2,3,19,6},i,n=6,odd,even; printf("The original data is:\n"); for(i=0;i<n;i++) printf("%5d",*(a+i...
编写一个函数计算出数组内所有奇数元素之和并作为函数返回值_百度知 ...答:include<stdio.h>void main(){ int sum(int a[],int length); int a[11] = {1,2,1,4,1,6,1,6,1,21,1}; printf("%d",sum(a,11));}int sum(int a[],int length){ int i,sum=0; for(i=0;i<length;i++) { if(i%2==0) { sum += a...