C#的,求一维数组中各元素的偶数之和。答:步骤:一、循环遍历数组中每一个元素 二、判断是否为偶数,若是,则相加 代码:int i = 0;int [] array = {1,2,3,4,5,6,7,8,9,10};int sum = 0;for(i = 0;i < array.Length;i ++){ if(array[i] % 2 ==0){ sum = sum + array[i];} } ...
求一维数组a中值为偶数的元素之和。求和要求使用子函数实现。例如,当...答:include <stdio.h>int sum(int arr[], int n);int main(){int a[] = {10, 4, 7, 3, 12, 5, 34, 5, 9};printf("%d\n", sum(a, 9));return 0;}int sum(int arr[], int n){int i, result = 0;for (i = 0; i < n; i++)if (arr[i] % 2 == 0)result ...