每根钢梁所受的力F=F总/10=220000/10=22000N
若取钢梁两支撑点间长3.8m,载荷均布在中间2m
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/203fb80e7bec54e7678502abbb389b504fc26a1d?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
如果采用简支法,则两支点的反力为Fa=Fb=11000N
最大弯矩在中点,Mmax=22000*3.8*(2-2/3.8)/8=15400Nm
以Q235为材料的话,屈服强度为235Mpa
则σ=M/W=M/(pi*d^3/32)=235
代入Mmax=15400Nm=15400000Nmm
解得d=87.4mm。
再乘以安全系数1.4的话,d安全=122mm
如果采用两端固定法安装梁,
![](https://video.ask-data.xyz/img.php?b=https://iknow-pic.cdn.bcebos.com/4bed2e738bd4b31c64638c0e85d6277f9e2ff82c?x-bce-process=image%2Fresize%2Cm_lfit%2Cw_600%2Ch_800%2Climit_1%2Fquality%2Cq_85%2Fformat%2Cf_auto)
则Mmax=22000*3.8*(3-3*2/3.8+2^2/3.8^2)/24=5914Nm