第2个回答 2012-04-16
#include <math.h>
#include <stdio.h>
main()
{
int n = 1, count =1;
double e = 1.0, term = 1.0;
long fac = 1;
for (n=1; fabs(term) >= 1e-4; n++)
{
fac = fac * n;
term = 1.0 / fac;
e = e + term;
count++;
}
printf("e = %f, count = %d\n", e, count);
}