写一个函数,接收两个数并返回其乘积,并用主函数调用它实现功能

Question

如题所述

Answer 1

#include <iostream>
using namespace std;
int power(int a,int b)
{
return a*b;
}
int main()
{
int a , b;
cout<<"请输入任意两个数"<<endl;
cin>>a>>b;
cout<<"结果为："<<power(a,b)<<endl;
return 0;
}

Answer 2

#include <stdio.h>
double fun(double x,double y)
{
return x*y;
}
void main
{
double m,n;
scanf("%lf %lf",&m,&n);
printf("m*n=%f",fun(m,n));
}追问

用c++

追答

#include
double fun(double x,double y)
{
return x*y;
}
void main
{
double m,n;
cin>>m;
cin>>n;
cout<<''m*n="<<fun(m,n)<<endl;
}

追问

void main 后面怎么没有（）

追答

不好意思，main()，丢掉了

本回答被提问者采纳

Answer 3

#include<stdio.h>
#include<math.h>
int chengji(int a,int b)
{
int m;
m=a*b;
return m;
}
void main()
{
int x,y,sum;

printf("请分别输入两个数x,y：");
scanf("%d %d",&x,&y);
sum=chengji(x,y);
printf("%d",sum);

}

Answer 4

chengji(int x,int y){
return x*y;
break;
}
main(){
int m,n;
scanf("%d%d"&m,&n);
printf("m和n的乘积为:",chengji(m,n);
)